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From the expression shown, $\lambda_m^{\infty}(HA) = 400 + 500 - 50$, the limiting molar conductivity of $HA$ is
A850
B950
C400
D50
Answer & Solution
Correct answer: A. 850
Direct evaluation gives $400 + 500 - 50 = 850$. Therefore, $\lambda_m^{\infty}(HA) = 850$.
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