Rajasthan Board Class 12 (RBSE) Current Electricity — practice questions
4 free MCQs with worked solutions. Tap any question for the answer + explanation, or practice them all in the app.
Practice Rajasthan Board Class 12 (RBSE) Current Electricity in the app →A bulb of resistance $240$ $\Omega$ is connected across $120$ V. Current through it is:A copper wire of length $L$ and area $A$ has resistance $R$. If length is doubled and area halved, the new resTwo resistors $3\ \Omega$ and $6\ \Omega$ are connected in parallel. The equivalent resistance is:A cell of EMF $1.5$ V and internal resistance $0.5\ \Omega$ delivers $1$ A to a bulb. Terminal voltage is: