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Rajasthan Board Class 10 (RBSE) Light - Reflection and Refraction — practice questions — page 2

Explore 57 free Light - Reflection and Refraction questions in Rajasthan Board Class 10 (RBSE) Science. Open each question or exercise to read its content, reference answers and available explanation.

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Light - Reflection and Refraction questions and exercises with answers

Showing questions 31–57 of 57.

In the mirror formula 1/v + 1/u = 1/f, what does u represent?Read the answer and worked solution →An object is placed 30 cm in front of a concave mirror of focal length 10 cm. The image distance is:Read the answer and worked solution →Magnification m for a spherical mirror is given by:Read the answer and worked solution →A 4 cm tall object placed at 20 cm gives an image at -40 cm (concave mirror). The image is:Read the answer and worked solution →When light passes from a rarer medium to a denser medium, it bends:Read the answer and worked solution →The absolute refractive index of a medium is the ratio of:Read the answer and worked solution →The refractive index of water is 1.33. The speed of light in water (in m/s) is approximately:Read the answer and worked solution →A ray of light travels from air into a glass slab. Which of the following changes is correct?Read the answer and worked solution →In a glass slab, a ray of light is refracted twice. The emergent ray is:Read the answer and worked solution →A convex lens forms a real image when the object is placed:Read the answer and worked solution →Power of a lens is measured in:Read the answer and worked solution →A lens has focal length 50 cm. Its power is:Read the answer and worked solution →A concave lens has a focal length of -25 cm. Its power is:Read the answer and worked solution →Two thin lenses of power +3 D and -1 D are kept in contact. The net power is:Read the answer and worked solution →A concave mirror with focal length 20 cm forms an image at 30 cm in front of it. The object is at:Read the answer and worked solution →For a concave mirror, magnification is +3 (virtual, erect, enlarged). If image is at +60 cm, object is at:Read the answer and worked solution →Which property of the image makes a convex mirror preferred for rear-view?Read the answer and worked solution →Lateral inversion in a plane mirror means:Read the answer and worked solution →Refractive index of medium A with respect to medium B is given by:Read the answer and worked solution →Light travelling from air strikes a water surface at 0° to the normal. The angle of refraction is:Read the answer and worked solution →A pencil partially dipped in water appears bent at the surface. This is due to:Read the answer and worked solution →A convex lens of focal length 20 cm produces a real image at distance 60 cm. The object is at:Read the answer and worked solution →A real image formed by a convex lens is:Read the answer and worked solution →The principal focus of a concave lens is:Read the answer and worked solution →A lens forms an image of an object placed at twice its focal length. The image is:Read the answer and worked solution →The focal length of a plane mirror is:Read the answer and worked solution →A diverging lens is also called:Read the answer and worked solution →

Worked practice questions

In the mirror formula 1/v + 1/u = 1/f, what does u represent?

  1. Image distance from pole
  2. Object distance from pole
  3. Focal length
  4. Radius of curvature
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Correct answer: B. Object distance from pole

1. The mirror formula relates v, u and f. 2. u is the object distance, measured from the pole. 3. v is the image distance and f the focal length. _Source: syllabus Science, Ch 9 "Light Reflection and Refraction", §9.2.4_

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An object is placed 30 cm in front of a concave mirror of focal length 10 cm. The image distance is:

  1. +15 cm
  2. -7.5 cm
  3. -15 cm
  4. -30 cm
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Correct answer: C. -15 cm

1. Apply 1/v + 1/u = 1/f with u = -30 cm, f = -10 cm. 2. 1/v = 1/f - 1/u = -1/10 + 1/30 = -3/30 + 1/30 = -2/30. 3. Hence v = -15 cm: the image is real, 15 cm in front of the mirror. _Source: syllabus Science, Ch 9 "Light Reflection and Refraction", §9.2.4_

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Magnification m for a spherical mirror is given by:

  1. m = v+u
  2. m = -u/v
  3. m = v×u
  4. m = -v/u
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Correct answer: D. m = -v/u

1. Magnification is the ratio of image height to object height. 2. Using the geometry of the mirror, this ratio equals -v/u. 3. A negative m indicates a real, inverted image. _Source: syllabus Science, Ch 9 "Light Reflection and Refraction", §9.2.4_

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