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PUCET (Punjab) Wheatstone Bridge — practice questions

Explore 3 free Wheatstone Bridge questions in PUCET (Punjab) Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Wheatstone Bridge questions and exercises with answers

Showing questions 1–3 of 3.

The balance condition for a Wheatstone bridge with arms $P, Q, R, S$ (galvanometer between B and D) is:Read the answer and worked solution →Wheatstone bridge is typically used to measure resistances in the range:Read the answer and worked solution →For a balanced Wheatstone bridge with $P = 1.36\ k\Omega$, $R = 300\ \Omega$ and $S = 4.4\ k\Omega$, the unknown $Q$ is approximately:Read the answer and worked solution →

Worked practice questions

The balance condition for a Wheatstone bridge with arms $P, Q, R, S$ (galvanometer between B and D) is:

  1. $P + Q = R + S$
  2. $P/Q = R/S$
  3. $P/Q = S/R$
  4. $PQ = RS$
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Correct answer: C. $P/Q = S/R$

At balance the galvanometer current $I_g = 0$. From the loop equations, $I_1P = I_2S$ and $I_1Q = I_2R$, dividing gives **P/Q = S/R**.

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Wheatstone bridge is typically used to measure resistances in the range:

  1. Above 10 GΩ only
  2. Tens to hundreds of ohms
  3. A few mΩ to 1 Ω
  4. MΩ to GΩ
Show answer and solution

Correct answer: B. Tens to hundreds of ohms

Wheatstone bridge is best suited for resistance values in tens to hundreds of ohms. For very low (mΩ) values, modified bridges (Kelvin double bridge) are used for very high values, special methods are needed.

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For a balanced Wheatstone bridge with $P = 1.36\ k\Omega$, $R = 300\ \Omega$ and $S = 4.4\ k\Omega$, the unknown $Q$ is approximately:

  1. ~5 kΩ
  2. ~200 kΩ
  3. ~19.94 kΩ
  4. ~0.5 kΩ
Show answer and solution

Correct answer: C. ~19.94 kΩ

Balance: $P/Q = R/S$ ⇒ $Q = PS/R = (1.36\times10^3)(4.4\times10^3)/300 \approx 19.94\times10^3\ \Omega \approx 19.94$ kΩ.

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