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PUCET (Punjab) Hydraulic Lift — practice questions

Explore 1 free Hydraulic Lift questions in PUCET (Punjab) Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Hydraulic Lift questions and exercises with answers

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A hydraulic lift uses a small piston (area 1 cm²) and a large piston (area 100 cm²). To lift a 1000 kg load, the minimum force needed on the small piston is:Read the answer and worked solution →

Worked practice questions

A hydraulic lift uses a small piston (area 1 cm²) and a large piston (area 100 cm²). To lift a 1000 kg load, the minimum force needed on the small piston is:

  1. 98 N
  2. 980 N
  3. 9.8 N
  4. 98,000 N
Show answer and solution

Correct answer: A. 98 N

Load weight = $1000 \times 9.8 = 9800$ N. Pascal: $F_1/A_1 = F_2/A_2$ ⇒ $F_1 = F_2 A_1/A_2 = 9800 \times (1/100) = 98$ N. Mechanical advantage = $A_2/A_1 = 100$.

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