When two inductors $L_1$ and $L_2$ are connected in **series** (no mutual inductance), the equivalent inductance is:
- $L_1 + L_2$
- $L_1 L_2/(L_1 + L_2)$
- $1/L_1 + 1/L_2$
- $\sqrt{L_1 L_2}$
Show answer and solution
Correct answer: A. $L_1 + L_2$
**Inductors in series add directly:** $L_{eq} = L_1 + L_2$ (analogous to resistors in series).
Parallel combination uses the reciprocal sum.