Start learning →

NMAT Number System — practice questions — page 4

Explore 136 free Number System questions in NMAT Quantitative Aptitude. Open each question or exercise to read its content, reference answers and available explanation.

Practise Number System with Quill →

Number System questions and exercises with answers

Showing questions 91–120 of 136.

With first term 6 and common difference 3, the first four terms are:Read the answer and worked solution →When the common difference is zero, as in 2, 2, 2, 2, the list is:Read the answer and worked solution →Gauss found the sum of the whole numbers from 1 to 100 to be:Read the answer and worked solution →The sum of the first n terms of a progression can be written as n by 2 times:Read the answer and worked solution →The sum of the first 22 terms of the list 8, 3, minus 2 is:Read the answer and worked solution →If the last term of a finite progression is l, the sum of all its terms is n by 2 times:Read the answer and worked solution →The sum of the first 1000 positive integers is:Read the answer and worked solution →If a, b and c are in a progression, then b equals:Read the answer and worked solution →A well costs 150 rupees for the first metre and rises by 50 for each further metre. The cost for the fourth metre is:Read the answer and worked solution →Catch the progressionsRead the answer and worked solution →Pop the progression wordsRead the answer and worked solution →Run the progression gatesRead the answer and worked solution →Slice the progression wordsRead the answer and worked solution →Progression or notRead the answer and worked solution →Sort term, sum and meanRead the answer and worked solution →Type the numberRead the answer and worked solution →Progressions bingoRead the answer and worked solution →The largest positive integer that divides both of two numbers is their:Read the answer and worked solution →The algorithm that finds that largest common divisor by repeated division is named after:Read the answer and worked solution →Using that algorithm on 455 and 42, the first step gives 455 = 42 times 10 plus:Read the answer and worked solution →Continuing, 42 = 35 times 1 plus 7, then 35 = 7 times 5 plus 0. The largest common divisor is:Read the answer and worked solution →The theorem saying every composite number can be written as a product of primes is the:Read the answer and worked solution →Writing 20 as 2 times 2 times 5 is an example of:Read the answer and worked solution →The highest common factor of 6 and 20 is:Read the answer and worked solution →The lowest common multiple of 6 and 20 is:Read the answer and worked solution →The highest common factor is found by taking, for each common prime, the:Read the answer and worked solution →The lowest common multiple is found by taking, for each prime involved, the:Read the answer and worked solution →For any two positive integers, the product of their highest common factor and lowest common multiple equals:Read the answer and worked solution →The prime factorisation of 96 gives a highest common factor with 404 of:Read the answer and worked solution →Using that result, the lowest common multiple of 96 and 404 is:Read the answer and worked solution →

Worked practice questions

With first term 6 and common difference 3, the first four terms are:

  1. 3, 6, 9, 12
  2. 6, 12, 18, 24
  3. 6, 9, 12, 15
  4. 6, 3, 0, minus 3
Show answer and solution

Correct answer: C. 6, 9, 12, 15

1. Start at 6. 2. Add 3 each time. 3. The terms are 6, 9, 12, 15. _Source: syllabus Mathematics, Chapter 5, Arithmetic Progressions._

Open this question →

When the common difference is zero, as in 2, 2, 2, 2, the list is:

  1. Never a progression
  2. A pure fraction
  3. A prime series
  4. Still a progression
Show answer and solution

Correct answer: D. Still a progression

1. The fixed number added is zero. 2. The difference may be positive, negative or zero. 3. It is still an arithmetic progression. _Source: syllabus Mathematics, Chapter 5, Arithmetic Progressions._

Open this question →

Gauss found the sum of the whole numbers from 1 to 100 to be:

  1. 5050
  2. 5500
  3. 1000
  4. 10000
Show answer and solution

Correct answer: A. 5050

1. He paired the list with its reverse. 2. That gives 100 pairs each summing to 101. 3. The sum is 5050. _Source: syllabus Mathematics, Chapter 5, Arithmetic Progressions._

Open this question →

How to practise

  1. Choose a Number System question and try to work out your answer.
  2. Open the question to check the correct answer and read its worked solution.
  3. Continue in the app for bite-sized lessons, explanations and review with Quill. You can start without creating an account.

More Quantitative Aptitude topics

Quantitative AptitudeAlgebraRatio and ProportionTime, Speed and DistanceTime and WorkPercentagesSimple InterestProfit and Loss