alleryStart learning →Three resistors of values 2 Ω, 3 Ω and 6 Ω are connected in parallel between two nodes. The equivalent resistance of the combination is:
- 0.5 Ω
- 11 Ω
- 2 Ω
- 1 Ω
Show answer and solution
Correct answer: D. 1 Ω
We have $1/R_{eq} = 1/2 + 1/3 + 1/6$.
That is $1/R_{eq} = 3/6 + 2/6 + 1/6$.
That is $1/R_{eq} = 6/6$.
So $1/R_{eq} = 1$.
⇒ $R_{eq} = 1\ \Omega$.
The parallel combination is always smaller than the smallest individual resistor.