Three resistors of values 2 Ω, 3 Ω and 6 Ω are connected in parallel between two nodes. The equivalent resistance of the combination is:

$1/R_{eq} = 1/2 + 1/3 + 1/6 = 3/6 + 2/6 + 1/6 = 6/6 = 1$ ⇒ $R_{eq} = 1\ \Omega$. The parallel combination is always smaller than the smallest individual resistor.