The half-life of a radioactive substance decaying by $dm/dt = -km$ (with $k > 0$) in terms of $k$ is:
- $\ln 2/k$
- $1/k$
- $k \ln 2$
- $2/k$
Show answer and solution
Correct answer: A. $\ln 2/k$
$m(t) = m_0 e^{-kt}$.
**Half-life:** $m_0/2 = m_0 e^{-kt_{1/2}}$
⇒ $kt_{1/2} = \ln 2$
⇒ $t_{1/2} = \ln 2/k$.