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MHT-CET Tangent — practice questions

3 free MCQs with worked solutions. Tap any question for the answer + explanation, or practice them all in the app.

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The **slope of the tangent** to the curve $y = f(x)$ at point $(a, f(a))$ is:The slope of the tangent to $y = x^3 - 3x + 1$ at $x = 2$ is:$y = x^3 - 6x^2 + x + 3$. The tangent is parallel to the line $y = x + 5$ at points where $x$ equals: