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The slope of the tangent to $y = x^3 - 3x + 1$ at $x = 2$ is:
A3
B6
C9
D12
Answer & Solution
Correct answer: C. 9
$y' = 3x^2 - 3$. At $x = 2$: $y' = 3(4) - 3 = 9$.
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