In triangle ABC, DE is parallel to BC where D lies on AB and E on AC. If AD = 2 cm, DB = 3 cm and AE = 4 cm, then EC equals
- 5 cm
- 8 cm
- 6 cm
- 10 cm
Show answer and solution
Correct answer: C. 6 cm
1. By the Basic Proportionality Theorem, AD/DB = AE/EC.
2. 2/3 = 4/EC.
3. Cross-multiply: 2 EC = 12, so EC = 6 cm.
_Source: syllabus Mathematics, Ch 6 "Triangles", §6.3_