The time period of a simple pendulum of length $L$ is:
- $T = 2\pi\sqrt{L/g}$
- $T = 2\pi\sqrt{g/L}$
- $T = 2\pi L/g$
- $T = 2\pi/g$
Show answer and solution
Correct answer: A. $T = 2\pi\sqrt{L/g}$
$T = 2\pi\sqrt{L/g}$.
Valid for small-angle approximation ($\theta < 10°$) where $\sin\theta \approx \theta$.