alleryThe time period of a simple pendulum of length $L$ is:
A$T = 2\pi\sqrt{L/g}$
B$T = 2\pi\sqrt{g/L}$
C$T = 2\pi L/g$
D$T = 2\pi/g$
Answer & Solution
Correct answer: A. $T = 2\pi\sqrt{L/g}$
$T = 2\pi\sqrt{L/g}$.
Valid for small-angle approximation ($\theta < 10°$) where $\sin\theta \approx \theta$.
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