JKCET Combination of Capacitors — practice questions

Explore 2 free Combination of Capacitors questions in JKCET Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Combination of Capacitors questions and exercises with answers

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When $n$ identical capacitors of capacitance $C$ are connected in series, the equivalent capacitance is:Read the answer and worked solution →Three capacitors of 4 μF each are connected: two in parallel, that combination in series with the third. The equivalent capacitance is:Read the answer and worked solution →

Worked practice questions

When $n$ identical capacitors of capacitance $C$ are connected in series, the equivalent capacitance is:

$nC$
$C$
$C/n$
$C^n$

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Correct answer: C. $C/n$

For $n$ identical capacitors in series, $1/C_{eq} = n/C$, hence $C_{eq} = C/n$. The series combination always gives a value smaller than the smallest individual capacitance.

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Three capacitors of 4 μF each are connected: two in parallel, that combination in series with the third. The equivalent capacitance is:

8.0 μF
2.67 μF
12.0 μF
1.33 μF

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Correct answer: B. 2.67 μF

**Two in parallel:** $4+4 = 8$ μF. In series with the third 4 μF: $1/C = 1/8 + 1/4 = 3/8$, so $C = 8/3 \approx 2.67$ μF. (Series with a larger capacitor pulls the equivalent below the smaller of the two.)