When $n$ identical capacitors of capacitance $C$ are connected in series, the equivalent capacitance is:
A$nC$
B$C$
C$C/n$
D$C^n$
Answer & Solution
Correct answer: C. $C/n$
For $n$ identical capacitors in series, $1/C_{eq} = n/C$, hence $C_{eq} = C/n$. The series combination always gives a value smaller than the smallest individual capacitance.
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