In a population, 16% individuals show a recessive phenotype (aa). Under Hardy-Weinberg, the frequency of the dominant allele A is:
- 0.16
- 0.40
- 0.60
- 0.84
Show answer and solution
Correct answer: C. 0.60
$q^2 = 0.16 \Rightarrow q = 0.40$.
**So $p = 1 - q = 0.60$.**