In a population, 16% individuals show a recessive phenotype (aa). Under Hardy-Weinberg, the frequency of the dominant allele A is:
A0.16
B0.40
C0.60
D0.84
Answer & Solution
Correct answer: C. 0.60
$q^2 = 0.16 \Rightarrow q = 0.40$. So $p = 1 - q = 0.60$.
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