At the **mean (equilibrium) position** of SHM, which is true?
- Velocity is zero, acceleration maximum
- Velocity is maximum, acceleration zero
- Both zero
- Both maximum
Show answer and solution
Correct answer: B. Velocity is maximum, acceleration zero
$v_{max} = A\omega$ at $x = 0$ (mean position).
$a = -\omega^2 x = 0$ there.
Conversely, at the extreme positions $x = \pm A$: $v = 0$, $|a| = \omega^2 A$ (max).