At the **mean (equilibrium) position** of SHM, which is true?
AVelocity is zero, acceleration maximum
BVelocity is maximum, acceleration zero
CBoth zero
DBoth maximum
Answer & Solution
Correct answer: B. Velocity is maximum, acceleration zero
$v_{max} = A\omega$ at $x = 0$ (mean position). $a = -\omega^2 x = 0$ there. Conversely, at the extreme positions $x = \pm A$: $v = 0$, $|a| = \omega^2 A$ (max).
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