JEECUP (UP Polytechnic) Gauss's Law — practice questions

Explore 2 free Gauss's Law questions in JEECUP (UP Polytechnic) Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Gauss's Law questions and exercises with answers

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Gauss's law for electric flux through a closed surface enclosing total charge $q$ is:Read the answer and worked solution →The electric field intensity at any point **inside** a uniformly charged hollow conducting sphere is:Read the answer and worked solution →

Worked practice questions

Gauss's law for electric flux through a closed surface enclosing total charge $q$ is:

$\oint \vec{E}\cdot d\vec{s} = \varepsilon_0 / q$
$\oint \vec{E}\cdot d\vec{s} = q / \varepsilon_0$
$\oint \vec{E}\cdot d\vec{s} = q / (4\pi\varepsilon_0)$
$\oint \vec{E}\cdot d\vec{s} = q\varepsilon_0$

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Correct answer: B. $\oint \vec{E}\cdot d\vec{s} = q / \varepsilon_0$

Gauss's law: total electric flux through any closed (Gaussian) surface equals $q/\varepsilon_0$, where $q$ is the net charge enclosed.

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The electric field intensity at any point inside a uniformly charged hollow conducting sphere is:

$q / (4\pi\varepsilon_0 R^2)$
$\sigma R / \varepsilon_0$
Zero
$\sigma / \varepsilon_0$

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Correct answer: C. Zero

Inside a hollow charged sphere a Gaussian surface encloses zero charge, so by Gauss's law E·4πr² = 0 and hence E = 0 everywhere inside.