When $n$ identical capacitors of capacitance $C$ are connected in series, the equivalent capacitance is:
- $nC$
- $C$
- $C/n$
- $C^n$
Show answer and solution
Correct answer: C. $C/n$
For $n$ identical capacitors in series, $1/C_{eq} = n/C$, hence $C_{eq} = C/n$.
The series combination always gives a value smaller than the smallest individual capacitance.