alleryThe distance between the points $(6,-4)$ and $(3,0)$ is:
- $\sqrt{41}$
- $\sqrt7$
- 7
- 5
Show answer and solution
Correct answer: D. 5
Distance = √[(6−3)²+(−4−0)²] = √(9+16) = √25 = 5.
JEE Main Straight Lines and Conic Sections — practice questions — page 2
Explore 77 free Straight Lines and Conic Sections questions in JEE Main Mathematics. Open each question or exercise to read its content, reference answers and available explanation.
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Showing questions 31–60 of 77.
The distance between the points $(6,-4)$ and $(3,0)$ is:Read the answer and worked solution →The acute angle between two lines with slopes $1$ and $0$ is:Read the answer and worked solution →The equation of the line with slope $2$ passing through $(1,3)$ is:Read the answer and worked solution →The distance of the point $(3,4)$ from the line $3x + 4y - 5 = 0$ is:Read the answer and worked solution →The x-intercept of the line $2x + 3y = 12$ is:Read the answer and worked solution →The slope of a line perpendicular to $y = 3x + 2$ is:Read the answer and worked solution →The slope of a vertical line (parallel to the y-axis) is:Read the answer and worked solution →A line passes through the origin and the point $(2,2)$. The angle it makes with the positive x-axis is:Read the answer and worked solution →The equation y² = 4ax represents a PARABOLA with:Read the answer and worked solution →The eccentricity of a CIRCLE is:Read the answer and worked solution →The standard form of a circle with centre (3, -2) and radius 5 is:Read the answer and worked solution →The HYPERBOLA x²/a² − y²/b² = 1 has asymptotes given by:Read the answer and worked solution →By Kepler's First Law, every planet orbits the Sun in:Read the answer and worked solution →A satellite dish uses a parabolic reflector because:Read the answer and worked solution →The Cassegrain telescope design uses the reflective property of a:Read the answer and worked solution →Complete the arc length relationRead the answer and worked solution →Match each identity to its nameRead the answer and worked solution →The Pythagorean identitiesRead the answer and worked solution →Odd function or even function?Read the answer and worked solution →Complete the degree and radian conversionRead the answer and worked solution →True or false: identities and parityRead the answer and worked solution →Match each sum or difference formula to its resultRead the answer and worked solution →Signs in the expansionRead the answer and worked solution →Which formula does this belong to?Read the answer and worked solution →True or false: periodicityRead the answer and worked solution →Complete the complementary angle rulesRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Order the steps: convert degrees to radiansRead the answer and worked solution →
Worked practice questions
The acute angle between two lines with slopes $1$ and $0$ is:
- $30^\circ$
- $60^\circ$
- $45^\circ$
- $90^\circ$
Show answer and solution
Correct answer: C. $45^\circ$
tanθ = |(1−0)/(1+1·0)| = 1, so θ = 45°.
The equation of the line with slope $2$ passing through $(1,3)$ is:
- $2x - y + 1 = 0$
- $x - 2y + 5 = 0$
- $2x - y - 1 = 0$
- $2x + y - 5 = 0$
Show answer and solution
Correct answer: A. $2x - y + 1 = 0$
We have y − 3 = 2(x − 1) ⟹ y.
That is y − 3 = 2x + 1 ⟹ 2x − y + 1.
So y − 3 = 0.
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