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JEE Advanced Unit 3A: Work and Kinetic Energy Theorem — practice questions — page 2

Explore 47 free Unit 3A: Work and Kinetic Energy Theorem questions in JEE Advanced Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Unit 3A: Work and Kinetic Energy Theorem questions and exercises with answers

Showing questions 31–47 of 47.

As per your syllabus, after 2 m of cord unwinds at 25 N pull, the work done by the pull is which?Read the answer and worked solution →As per your syllabus, the work done by an external torque equals which?Read the answer and worked solution →Match each SI unit to the quantity it measures.Read the answer and worked solution →Match each kinematic equation to what it computes (constant a).Read the answer and worked solution →Pop only the good thermal conductors.Read the answer and worked solution →Match each SI unit to the quantity it measures.Read the answer and worked solution →Match each kinematic equation to what it computes (constant a).Read the answer and worked solution →Pop only the good thermal conductors.Read the answer and worked solution →Newton's second law of motion.Read the answer and worked solution →Ohm's law.Read the answer and worked solution →Kinetic energy formula.Read the answer and worked solution →Match the SI unit to the quantityRead the answer and worked solution →Match the quantity to its dimensional formulaRead the answer and worked solution →Which planet has the higher surface gravity?Read the answer and worked solution →Conservative or non-conservative?Read the answer and worked solution →Match the SHM quantity to its formulaRead the answer and worked solution →Match the rotational quantity to its linear analogRead the answer and worked solution →

Worked practice questions

As per your syllabus, after 2 m of cord unwinds at 25 N pull, the work done by the pull is which?

  1. 100 J
  2. 12.5 J
  3. 25 J
  4. 50 J
Show answer and solution

Correct answer: D. 50 J

syllabus Ex 6.12(b): W = F × distance = 25 × 2 = 50 J. Equals KE gained (energy conservation).

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As per your syllabus, the work done by an external torque equals which?

  1. Heat dissipated
  2. Loss due to friction
  3. Zero in steady rotation
  4. The change in rotational KE
Show answer and solution

Correct answer: D. The change in rotational KE

Your syllabus: no internal motion, no friction ⇒ τω = d/dt((1/2)Iω²) ⇒ W_ext = ΔK_rot. Work-energy theorem in rotation.

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Match each SI unit to the quantity it measures.

Read exercise and reference answers
Matching pairs
  1. Left
    newton (N)
    Right
    Force
  2. Left
    pascal (Pa)
    Right
    Pressure
  3. Left
    joule (J)
    Right
    Energy / Work
Instructions
Pair each unit with its quantity.
_Source: syllabus Physics, Ch 2 'Units and Measurements' Table 2.2_

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