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ISC Class 12 Aldehydes, Ketones and Carboxylic Acids — practice questions — page 2

Explore 56 free Aldehydes, Ketones and Carboxylic Acids questions in ISC Class 12 Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Aldehydes, Ketones and Carboxylic Acids questions and exercises with answers

Showing questions 31–56 of 56.

The **Gattermann reaction** (not Gatterman–Koch) converts $ArN_2^+X^-$ to $ArX$ usingRead the answer and worked solution →The Wurtz–Fittig reaction between $C_6H_5Br$ and $CH_3CH_2Br$ with Na in dry ether givesRead the answer and worked solution →The **Balz–Schiemann reaction** converts $ArN_2^+$ to $ArF$ via which intermediate?Read the answer and worked solution →Friedel–Crafts alkylation of benzene with $1$-chloropropane and $AlCl_3$ gives, as the major product,Read the answer and worked solution →A **Grignard reagent** has the general formulaRead the answer and worked solution →**Stephen's reduction** converts a nitrile $RCN$ into an aldehyde usingRead the answer and worked solution →In the **cumene process** for industrial phenol production, the by-product formed alongside phenol isRead the answer and worked solution →The **Swarts reaction** converts an alkyl chloride to an alkyl fluoride usingRead the answer and worked solution →**Cannizzaro's reaction** is given by aldehydes that haveRead the answer and worked solution →**Diazotisation** of a primary aromatic amine uses $NaNO_2 + HCl$ atRead the answer and worked solution →Which reaction is being described?Read the answer and worked solution →The reaction of $CH_3MgBr$ with formaldehyde ($HCHO$), followed by acidic workup, givesRead the answer and worked solution →**Lucas reagent** is a mixture ofRead the answer and worked solution →In **Wurtz's reaction**, two alkyl halides couple in the presence ofRead the answer and worked solution →Self-aldol condensation of acetaldehyde, after dehydration, givesRead the answer and worked solution →**Rosenmund's reduction** converts an acyl chloride to an aldehyde usingRead the answer and worked solution →The **Hell–Volhard–Zelinsky (HVZ) reaction** converts a carboxylic acid (with $\alpha$-H) to an $\alpha$-halo acid usingRead the answer and worked solution →Identify the correct conversion: $CH_3CN \xrightarrow{?} CH_3CHO$ (one step).Read the answer and worked solution →In **Dow's process**, chlorobenzene is converted to phenol by treatment withRead the answer and worked solution →**Gatterman–Koch reaction** formylates benzene usingRead the answer and worked solution →Among $1$-butanol, $2$-butanol and $tert$-butanol, the order of reactivity in the Lucas test isRead the answer and worked solution →Match each named organic reaction to its description.Read the answer and worked solution →The product of the Hunsdiecker reaction on $CH_3CH_2COOAg$ with $Br_2/CCl_4$ isRead the answer and worked solution →Match each named organic reaction to its description.Read the answer and worked solution →Which of the following named reactions does **NOT** require an $\alpha$-hydrogen on the substrate?Read the answer and worked solution →The IUPAC name of the simplest aldehyde, $\mathrm{HCHO}$, isRead the answer and worked solution →

Worked practice questions

The **Gattermann reaction** (not Gatterman–Koch) converts $ArN_2^+X^-$ to $ArX$ using

  1. $Cu$ powder / $HX$
  2. $LiAlH_4$
  3. $Cu_2X_2$ / $HX$
  4. $NaOH$
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Correct answer: A. $Cu$ powder / $HX$

Gattermann uses freshly precipitated **Cu powder** with the corresponding HX. Sandmeyer uses $Cu_2X_2$. Gattermann gives lower yields but uses simpler reagents.

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The Wurtz–Fittig reaction between $C_6H_5Br$ and $CH_3CH_2Br$ with Na in dry ether gives

  1. n-Butane
  2. Biphenyl
  3. Ethylbenzene
  4. Toluene
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Correct answer: C. Ethylbenzene

Wurtz–Fittig: $C_6H_5Br + CH_3CH_2Br + 2\,Na \to C_6H_5-CH_2CH_3 + 2\,NaBr$. The mixed coupling between aryl and alkyl halides gives ethylbenzene as the desired product (with biphenyl and butane as side-products).

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The **Balz–Schiemann reaction** converts $ArN_2^+$ to $ArF$ via which intermediate?

  1. $ArOH + HF$
  2. $ArN_2^+ BF_4^-$ (then $\Delta$)
  3. $ArMgBr + F_2$
  4. $ArN_2^+ Cl^- + AgF$
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Correct answer: B. $ArN_2^+ BF_4^-$ (then $\Delta$)

$ArN_2^+Cl^- + HBF_4 \to ArN_2^+BF_4^-\downarrow$. The dry tetrafluoroborate salt, on gentle heating, decomposes to $ArF + N_2\uparrow + BF_3$. The only practical lab route to aryl fluorides from amines.

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More Chemistry topics

Amines and BiomoleculesChemical KineticsThe d- and f-Block Elements & Coordination CompoundsElectrochemistryHaloalkanes, Alcohols and EthersSolutions