Vector $\vec{AB} = 2\hat i - 4\hat j + 7\hat k$ has initial point $A(1, 5, 0)$. The terminal point $B$ has coordinates:
- $(3, 1, 7)$
- $(-1, 9, -7)$
- $(2, -4, 7)$
- $(3, -4, 7)$
Show answer and solution
Correct answer: A. $(3, 1, 7)$
$\vec{AB} = \vec b - \vec a$
⇒ $\vec b = \vec a + \vec{AB} = (1+2)\hat i + (5-4)\hat j + (0+7)\hat k = 3\hat i + \hat j + 7\hat k$, i.e. $B = (3, 1, 7)$.