Vector $\vec{AB} = 2\hat i - 4\hat j + 7\hat k$ has initial point $A(1, 5, 0)$. The terminal point $B$ has coordinates:
A$(3, 1, 7)$
B$(-1, 9, -7)$
C$(2, -4, 7)$
D$(3, -4, 7)$
Answer & Solution
Correct answer: A. $(3, 1, 7)$
$\vec{AB} = \vec b - \vec a$ ⇒ $\vec b = \vec a + \vec{AB} = (1+2)\hat i + (5-4)\hat j + (0+7)\hat k = 3\hat i + \hat j + 7\hat k$, i.e. $B = (3, 1, 7)$.
Related questions
The work done by a constant force F in displacement d isIf a, b, c are mutually perpendicular unit vectors, the value of a · (b × c) isIf position vectors of A and B are a and b respectively, then mid-point of AB has positionVectors a and b are collinear iffVolume of a parallelepiped with edges a, b, c isArea of the parallelogram having adjacent sides a and b isIf a = 2i + 3j − k and b = i − j + 2k then a · b equalsUnit vector along the vector i + j + k is