Vector $\vec{AB} = 2\hat i - 4\hat j + 7\hat k$ has initial point $A(1, 5, 0)$. The terminal point $B$ has coordinates:
A$(3, 1, 7)$
B$(-1, 9, -7)$
C$(2, -4, 7)$
D$(3, -4, 7)$
Answer & Solution
Correct answer: A. $(3, 1, 7)$
$\vec{AB} = \vec b - \vec a$ ⇒ $\vec b = \vec a + \vec{AB} = (1+2)\hat i + (5-4)\hat j + (0+7)\hat k = 3\hat i + \hat j + 7\hat k$, i.e. $B = (3, 1, 7)$.
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