The order and degree of $\sqrt{1 + (dy/dx)^2} = d^2y/dx^2$ are:
- 2, 1
- 2, 2
- 1, 2
- 1, 1
Show answer and solution
Correct answer: B. 2, 2
**Square both sides:** $1 + (dy/dx)^2 = (d^2y/dx^2)^2$.
Highest derivative $d^2y/dx^2$ → order 2; its power → degree 2.