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The order and degree of $\sqrt{1 + (dy/dx)^2} = d^2y/dx^2$ are:
A2, 1
B2, 2
C1, 2
D1, 1
Answer & Solution
Correct answer: B. 2, 2
Square both sides: $1 + (dy/dx)^2 = (d^2y/dx^2)^2$. Highest derivative $d^2y/dx^2$ → order 2; its power → degree 2.
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