A simple pendulum of length 1 m on Earth (g = 10) has frequency:
- Approximately 1/π Hz
- 10 Hz
- 0.5 Hz
- 2 Hz
Show answer and solution
Correct answer: A. Approximately 1/π Hz
We have T = 2π√(L/g).
That is T = 2π√(1/10).
So T = 2π × 0.316 ≈ 1.987 s.
f = 1/T ≈ 0.503 Hz, which is approximately 1/π.
Both options A and B are close; B is more precise.