A simple pendulum of length 1 m on Earth (g = 10) has frequency:
AApproximately 1/π Hz
B10 Hz
C0.5 Hz
D2 Hz
Answer & Solution
Correct answer: A. Approximately 1/π Hz
We have T = 2π√(L/g).
That is T = 2π√(1/10).
So T = 2π × 0.316 ≈ 1.987 s.
f = 1/T ≈ 0.503 Hz, which is approximately 1/π.
Both options A and B are close; B is more precise.
Keep practising Unit 1C: Kinematics: Relative & Circular Motion
Browse all Unit 1C: Kinematics: Relative & Circular Motion questions for AP Physics 1, or explore more Physics topics.
Related questions
A solid sphere of mass M, radius R rolls without slipping down an incline of angle theta. For a hoop, disc, and solid sphere of same mass and radius rolling down an incline. Order A figure skater pulls in her arms during a spin. Her moment of inertia decreases. By conseTwo point masses 3 kg each at the ends of a massless rod of length 4 m. I about axis throuA solid cylinder and a hollow cylinder of same mass and radius roll down an incline. WhichFor a body rolling without slipping with velocity v of center of mass:Kinetic energy of a rotating body with moment of inertia I and angular velocity omega:For a thin rod of mass M and length L, I about axis through center perpendicular to rod: