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A simple pendulum of length 1 m on Earth (g = 10) has frequency:

AApproximately 1/π Hz
B10 Hz
C0.5 Hz
D2 Hz
Answer & Solution
Correct answer: A. Approximately 1/π Hz
We have T = 2π√(L/g). That is T = 2π√(1/10). So T = 2π × 0.316 ≈ 1.987 s. f = 1/T ≈ 0.503 Hz, which is approximately 1/π. Both options A and B are close; B is more precise.
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