The universal gravitational constant $G$ has the SI value approximately:
- $6.67 \times 10^{-11}\,\mathrm{N\,m^2/kg^2}$
- $9.81\,\mathrm{m/s^2}$
- $6.022 \times 10^{23}\,\mathrm{/mol}$
- $1.6 \times 10^{-19}\,\mathrm{C}$
Show answer and solution
Correct answer: A. $6.67 \times 10^{-11}\,\mathrm{N\,m^2/kg^2}$
Universal gravitational constant $G = 6.67 \times 10^{-11}$ N·m²/kg² in SI units, the same everywhere in the universe.
The units come from Newton's law $F = G m_1 m_2 / r^2$: $\dfrac{\text{kg} \cdot \text{kg}}{\text{m}^2} \cdot [G] = \text{N}$
so $[G] = \text{N} \cdot \text{m}^2 / \text{kg}^2$.
Option B is the local acceleration due to gravity $g$ (not constant). Option C is Avogadro. Option D is the electronic charge.