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As per your syllabus, + Example 7.7, for the Moon's orbit (R ≈ 3.84 × 10⁵ km), the time period computed from k = 1.33 × 10⁻¹⁴ d² km⁻³ is approximately which?
A27.3 days
B85 minutes
C30.0 days
D365 days
Answer & Solution
Correct answer: A. 27.3 days
syllabus Ex 7.7: T² = kR³ = 1.33×10⁻¹⁴ × (3.84×10⁵)³ ⇒ T ≈ 27.3 days.
Matches observed lunar period.
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