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Indian Navy INET Surface Areas and Volumes — practice questions

Explore 6 free Surface Areas and Volumes questions in Indian Navy INET Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Surface Areas and Volumes questions and exercises with answers

Showing questions 1–6 of 6.

Worked practice questions

The direction ratios of the line joining the points $(1,2,3)$ and $(4,5,6)$ are:

  1. $4, 5, 6$
  2. $3, 3, 3$
  3. $1, 2, 3$
  4. $5, 7, 9$
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Correct answer: B. $3, 3, 3$

Direction ratios = differences of coordinates: (4−1, 5−2, 6−3) = (3,3,3).

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The cosine of the angle between two lines with direction ratios $(1,2,2)$ and $(2,2,1)$ is:

  1. $\tfrac{4}{9}$
  2. $\tfrac{2}{3}$
  3. $\tfrac{1}{9}$
  4. $\tfrac{8}{9}$
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Correct answer: D. $\tfrac{8}{9}$

We have cosθ = (1·2+2·2+2·1)/(√9·√9). So cosθ = 8/9.

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A cylindrical glass tube of radius 1 cm is filled with water to depth 14 cm. A sphere of radius 1 cm is dropped in. The new water level rises by

  1. 2 cm
  2. 2/3 cm
  3. 1 cm
  4. 4/3 cm
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Correct answer: D. 4/3 cm

1. Sphere volume = (4/3) × pi × 1 cubed = (4/3) pi cu cm. 2. Cross-section = pi × 1 squared = pi. 3. Rise = (4/3) pi / pi = 4/3 cm. _Source: syllabus Mathematics, Ch 12 "Surface Areas and Volumes", §12.3_

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