If $f(x)$ is an **even** function, then $\int_{-a}^{a} f(x)\,dx$ equals:
- $0$
- $\int_0^a f(x)\,dx$
- $2\int_0^a f(x)\,dx$
- $-2\int_0^a f(x)\,dx$
Show answer and solution
Correct answer: C. $2\int_0^a f(x)\,dx$
For even $f$: $f(-x) = f(x)$, so the contributions from $[-a, 0]$ and $[0, a]$ are equal.
**Thus $\int_{-a}^{a} f = 2\int_0^a f$.**