$\int_0^4 (x - x^2)\,dx$ equals:
- $-40/3$
- $8$
- $40/3$
- $-8$
Show answer and solution
Correct answer: A. $-40/3$
**Antiderivative:** $x^2/2 - x^3/3$.
**Evaluate:** $[x^2/2 - x^3/3]_0^4 = (16/2 - 64/3) - 0 = 8 - 64/3 = (24-64)/3 = -40/3$.
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Correct answer: A. $-40/3$