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IBPS RRB Officer Scale 1 Quadratic Equations — practice questions

Explore 33 free Quadratic Equations questions in IBPS RRB Officer Scale 1 Quantitative Aptitude. Open each question or exercise to read its content, reference answers and available explanation.

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Quadratic Equations questions and exercises with answers

Showing questions 1–30 of 33.

If x² − 15x + 56 = 0 and y = √64, establish the relation between x and y.Read the answer and worked solution →If x² − 6x + 9 = 0 and y² − 3y − 18 = 0, what is the relation between x and y?Read the answer and worked solution →If 4x² + 12x + 9 = 0 and 2y² + 11y + 14 = 0, establish the relation between x and y.Read the answer and worked solution →A hall's carpet area is 300 square metres and its length is one metre more than twice its breadth. Setting up this problem gives a:Read the answer and worked solution →For the prayer hall, the breadth comes out as 12 m and the length as:Read the answer and worked solution →Solving the hall equation gives x = 12 or x = minus 12.5. The negative value is rejected because:Read the answer and worked solution →Who are believed to have been the first to solve quadratic equations?Read the answer and worked solution →Which Greek mathematician found lengths that solve quadratic equations by a geometric approach?Read the answer and worked solution →The formula now called the quadratic formula was derived in C.E. 1025 by:Read the answer and worked solution →Al-Khwarizmi, who studied several types of quadratic equations around C.E. 800, was a mathematician from:Read the answer and worked solution →John and Jivanti had 45 marbles together. After each lost 5, the product of their marbles was 124. This leads to a:Read the answer and worked solution →Each toy cost 55 minus the number of toys made that day. Total cost 750. The unknown number satisfies:Read the answer and worked solution →Before deciding whether an equation is quadratic, you often need to:Read the answer and worked solution →An equation that looks cubic may turn out, after simplifying, to be:Read the answer and worked solution →The zeroes of the quadratic polynomial and the roots of the matching quadratic equation are:Read the answer and worked solution →Factorising splits the quadratic into two linear factors; the roots come from setting each factor to:Read the answer and worked solution →Splitting the middle term to factorise a quadratic was learnt in which class?Read the answer and worked solution →When a factor is repeated, the root is:Read the answer and worked solution →Sunita's age satisfies x squared equals 9. Her present age is:Read the answer and worked solution →Besides factorisation, a quadratic can be solved by the method of:Read the answer and worked solution →b squared minus 4ac is called the:Read the answer and worked solution →If the discriminant is zero, the two roots are:Read the answer and worked solution →A negative discriminant means no real roots because no real number has a negative:Read the answer and worked solution →A pole must be 7 m farther from gate A than gate B on a circular park of diameter 13 m. The pole goes:Read the answer and worked solution →Solutions of a word problem should be verified against:Read the answer and worked solution →Catch the quadratic makersRead the answer and worked solution →Pop the quadratic pioneersRead the answer and worked solution →Steer into the quadratic laneRead the answer and worked solution →Slice the quadratic wordsRead the answer and worked solution →Real or notRead the answer and worked solution →

Worked practice questions

If x² − 15x + 56 = 0 and y = √64, establish the relation between x and y.

  1. x ≤ y
  2. x ≥ y
  3. x > y
  4. x < y
Show answer and solution

Correct answer: A. x ≤ y

1. x² − 15x + 56 = 0 factors as (x − 7)(x − 8) = 0, so x = 7 or 8. 2. y = √64 = 8 (principal square root). 3. Both possible x values (7 and 8) are ≤ 8, so **x ≤ y**. _Source: IBPS RRB Officer Scale I Prelims PYQ (Examrace), Q.41_

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If x² − 6x + 9 = 0 and y² − 3y − 18 = 0, what is the relation between x and y?

  1. x is always greater than y
  2. x is always less than y
  3. x and y have no fixed relation
  4. x is always equal to y
Show answer and solution

Correct answer: C. x and y have no fixed relation

1. x² − 6x + 9 = (x − 3)² = 0 ⇒ x = 3. 2. y² − 3y − 18 = (y − 6)(y + 3) = 0 ⇒ y = 6 or y = −3. 3. Against x = 3: y = 6 gives x < y, but y = −3 gives x > y — so **no fixed relation** holds. _Source: IBPS RRB Officer Scale I Prelims PYQ (Examrace), Q.42_

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If 4x² + 12x + 9 = 0 and 2y² + 11y + 14 = 0, establish the relation between x and y.

  1. x > y
  2. x < y
  3. x ≤ y
  4. x = y
Show answer and solution

Correct answer: A. x > y

1. 4x² + 12x + 9 = (2x + 3)² = 0 ⇒ x = −1.5. 2. 2y² + 11y + 14 = 0 ⇒ y = (−11 ± √(121 − 112))/4 = (−11 ± 3)/4 ⇒ y = −2 or −3.5. 3. x = −1.5 is greater than both −2 and −3.5, so **x > y**. _Source: IBPS RRB Officer Scale I Prelims PYQ (Examrace), Q.45_

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