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If x² − 15x + 56 = 0 and y = √64, establish the relation between x and y.
Ax ≤ y
Bx ≥ y
Cx > y
Dx < y
Answer & Solution
Correct answer: A. x ≤ y
1. x² − 15x + 56 = 0 factors as (x − 7)(x − 8) = 0, so x = 7 or 8.
2. y = √64 = 8 (principal square root).
3. Both possible x values (7 and 8) are ≤ 8, so **x ≤ y**.
_Source: IBPS RRB Officer Scale I Prelims PYQ (Examrace), Q.41_
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