The **moment of inertia** of a thin uniform rod of mass $M$ and length $L$ about a perpendicular axis through its **centre** is:
- $ML^2/3$
- $ML^2/12$
- $ML^2/2$
- $ML^2$
Show answer and solution
Correct answer: B. $ML^2/12$
**Standard result:** $I_{\text{cm}} = ML^2/12$.
**About one end (parallel axis):** $I = ML^2/12 + M(L/2)^2 = ML^2/3$.