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The **moment of inertia** of a thin uniform rod of mass $M$ and length $L$ about a perpendicular axis through its **centre** is:
A$ML^2/3$
B$ML^2/12$
C$ML^2/2$
D$ML^2$
Answer & Solution
Correct answer: B. $ML^2/12$
Standard result: $I_{\text{cm}} = ML^2/12$. About one end (parallel axis): $I = ML^2/12 + M(L/2)^2 = ML^2/3$.
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