HPCET Cell Constant — practice questions

Explore 2 free Cell Constant questions in HPCET Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Cell Constant questions and exercises with answers

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**Cell constant** of a conductivity cell is given by:Read the answer and worked solution →A conductivity cell containing 0.01 M KCl ($\kappa = 0.00141$ Ω⁻¹ cm⁻¹) at 25 °C has resistance 604 Ω. The cell constant is:Read the answer and worked solution →

Worked practice questions

Cell constant of a conductivity cell is given by:

$\Lambda \cdot c$
$l/a$ (separation/area)
$R/\kappa$
$\kappa \cdot R$

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Correct answer: B. $l/a$ (separation/area)

Cell constant $= l/a$ — has SI units m⁻¹ (commonly cm⁻¹). Once known (typically calibrated with KCl), gives $\kappa = \text{cell constant}/R$.

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A conductivity cell containing 0.01 M KCl ($\kappa = 0.00141$ Ω⁻¹ cm⁻¹) at 25 °C has resistance 604 Ω. The cell constant is:

$0.852$ cm⁻¹
$1.704$ cm⁻¹
$0.426$ cm⁻¹
$2.84$ cm⁻¹

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Correct answer: A. $0.852$ cm⁻¹

Cell constant $= \kappa_{KCl} \times R = 0.00141 \times 604 = 0.852$ cm⁻¹.