A conductivity cell containing 0.01 M KCl ($\kappa = 0.00141$ Ω⁻¹ cm⁻¹) at 25 °C has resistance 604 Ω. The cell constant is:
A$0.852$ cm⁻¹
B$1.704$ cm⁻¹
C$0.426$ cm⁻¹
D$2.84$ cm⁻¹
Answer & Solution
Correct answer: A. $0.852$ cm⁻¹
Cell constant $= \kappa_{KCl} \times R = 0.00141 \times 604 = 0.852$ cm⁻¹.
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