For outcomes w1, ..., wn of S, the sum of P(wi) equals
- 0
- 1
- 1/n
- n
Show answer and solution
Correct answer: B. 1
The outcomes together make up S, and P(S) is 1, so their probabilities sum to 1.
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Correct answer: B. 1
Correct answer: C. 3/4
Correct answer: C. 0.7
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