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GMAT Statistics and Probability — practice questions

Explore 198 free Statistics and Probability questions in GMAT Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Statistics and Probability questions and exercises with answers

Showing questions 1–30 of 198.

Harpreet tosses two different coins simultaneously. What is the probability of getting at least one head?Read the answer and worked solution →Savita and Hamida are friends. Ignoring leap year, what is the probability that they have the same birthday?Read the answer and worked solution →One card is drawn from a well-shuffled deck of 52 cards. What is the probability that the card is not an ace?Read the answer and worked solution →If $P(E)=0.62$, what is $P(\overline{E})$?Read the answer and worked solution →An event having only one outcome of an experiment is calledRead the answer and worked solution →The probability of getting HEADS when flipping a fair coin is:Read the answer and worked solution →The probability of rolling a 3 on a fair six-sided die is:Read the answer and worked solution →What is the probability of rolling an EVEN number on a fair six-sided die?Read the answer and worked solution →A class of 30 students has 18 girls. The probability that a randomly chosen student is a BOY is:Read the answer and worked solution →The arithmetic mean of n values x1, x2, ..., xn is:Read the answer and worked solution →Median of an odd-length sorted data set is:Read the answer and worked solution →Probability of a certain event:Read the answer and worked solution →Probability of rolling a 6 on a fair die:Read the answer and worked solution →For independent events A and B, P(A and B) equals:Read the answer and worked solution →For mutually exclusive events A and B, P(A or B) equals:Read the answer and worked solution →Find mean of {2, 4, 6, 8, 10}:Read the answer and worked solution →Variance of {2, 4, 6, 8, 10}:Read the answer and worked solution →Standard deviation of {2, 4, 6, 8, 10}:Read the answer and worked solution →P(at least one head in 2 fair coin tosses):Read the answer and worked solution →Probability of drawing a heart from a standard 52-card deck:Read the answer and worked solution →The theoretical probability of an event E is:Read the answer and worked solution →The probability of a sure (certain) event is:Read the answer and worked solution →The probability of an impossible event is:Read the answer and worked solution →The probability of any event E always lies between:Read the answer and worked solution →For any event E, the sum P(E) + P(not E) equals:Read the answer and worked solution →The probability of getting a head when an unbiased coin is tossed once is:Read the answer and worked solution →The probability of getting a 3 when a fair die is rolled once is:Read the answer and worked solution →The probability of getting an even number on a single roll of a fair die is:Read the answer and worked solution →The probability of drawing a red card from a well-shuffled deck of 52 cards is:Read the answer and worked solution →The probability of drawing an ace from a well-shuffled deck of 52 cards is:Read the answer and worked solution →

Worked practice questions

Harpreet tosses two different coins simultaneously. What is the probability of getting at least one head?

  1. $\frac{1}{4}$
  2. $\frac{1}{2}$
  3. $\frac{3}{4}$
  4. $1$
Show answer and solution

Correct answer: C. $\frac{3}{4}$

The equally likely outcomes are $(H,H)$, $(H,T)$, $(T,H)$ and $(T,T)$. At least one head occurs in the first three outcomes, so there are 3 favourable outcomes out of 4. Thus the probability is $\frac{3}{4}$.

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Savita and Hamida are friends. Ignoring leap year, what is the probability that they have the same birthday?

  1. $\frac{1}{364}$
  2. $\frac{1}{365}$
  3. $\frac{364}{365}$
  4. $\frac{2}{365}$
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Correct answer: B. $\frac{1}{365}$

Fix Savita's birthday on any day. Hamida can have any of 365 equally likely birthdays, and only 1 of these matches Savita's. **So the probability of the same birthday is $\frac{1}{365}$.**

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One card is drawn from a well-shuffled deck of 52 cards. What is the probability that the card is not an ace?

  1. $\frac{1}{13}$
  2. $\frac{4}{13}$
  3. $\frac{12}{13}$
  4. $\frac{48}{13}$
Show answer and solution

Correct answer: C. $\frac{12}{13}$

A deck has 4 aces, so non-aces are $52-4=48$. Hence the probability is $\frac{48}{52}=\frac{12}{13}$. Equivalently, it is $1-\frac{1}{13}=\frac{12}{13}$.

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More Mathematics topics

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