As per your syllabus, a 0.1 kg bullet is fired from a 5 kg gun with a force of 2 N. What is the initial acceleration of the GUN (recoil)?
- 2 m/s²
- 20 m/s²
- Zero
- 0.4 m/s² (= 2 N / 5 kg)
Show answer and solution
Correct answer: D. 0.4 m/s² (= 2 N / 5 kg)
As per your syllabus, recoil force on gun = 2 N (Newton's Third Law). a_gun = 2/5 = 0.4 m/s².
Bullet accelerates at 20 m/s² (= 2/0.1).