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DSSSB TGT C9newtonsecond — practice questions

Explore 4 free C9newtonsecond questions in DSSSB TGT Physics. Open each question or exercise to read its content, reference answers and available explanation.

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C9newtonsecond questions and exercises with answers

Showing questions 1–4 of 4.

As per your syllabus, Science, Newton's SECOND law of motion in mathematical form is which?Read the answer and worked solution →As per your syllabus, what is 1 NEWTON of force formally defined as?Read the answer and worked solution →As per your syllabus, what is the approximate value of g (acceleration due to gravity) near the Earth's surface?Read the answer and worked solution →As per your syllabus, a 30 kg barbell is held STEADY by a weightlifter. How much UPWARD force must she apply (taking g = 9.8 m/s²)?Read the answer and worked solution →

Worked practice questions

As per your syllabus, Science, Newton's SECOND law of motion in mathematical form is which?

  1. F = m × v
  2. F = m/a
  3. F = m + a
  4. F = ma (force equals mass times acceleration)
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Correct answer: D. F = ma (force equals mass times acceleration)

As per your syllabus, Eq 6.2, F = ma. The other formulas misstate.

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As per your syllabus, what is 1 NEWTON of force formally defined as?

  1. The weight of a person
  2. Equal to 1 joule
  3. 1 newton = 1 kg
  4. The force that produces an acceleration of 1 m/s² on an object of mass 1 kg
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Correct answer: D. The force that produces an acceleration of 1 m/s² on an object of mass 1 kg

As per your syllabus, 1 N = 1 kg × 1 m/s² = 1 kg m s⁻² (per Newton's Second Law).

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As per your syllabus, what is the approximate value of g (acceleration due to gravity) near the Earth's surface?

  1. g ≈ 100 m/s²
  2. g ≈ 9.8 m/s² (often rounded to 10 m/s² in calculations)
  3. g ≈ 1 m/s²
  4. g ≈ 0 m/s²
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Correct answer: B. g ≈ 9.8 m/s² (often rounded to 10 m/s² in calculations)

As per your syllabus, g ≈ 9.8 m/s² (or 10 m/s² for quick estimates). The other values misstate.

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