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DSSSB TGT C10mirrorformula — practice questions

Explore 5 free C10mirrorformula questions in DSSSB TGT Physics. Open each question or exercise to read its content, reference answers and available explanation.

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C10mirrorformula questions and exercises with answers

Showing questions 1–5 of 5.

As per your syllabus, what is the MIRROR FORMULA — relating object distance (u), image distance (v), and focal length (f)?Read the answer and worked solution →As per your syllabus, a NEGATIVE value of magnification m for a mirror indicates what?Read the answer and worked solution →As per your syllabus, if the radius of curvature of a spherical mirror is 20 cm, what is its focal length?Read the answer and worked solution →As per your syllabus, if a CONVEX MIRROR has R = 3.00 m, what is its FOCAL LENGTH (with sign)?Read the answer and worked solution →As per your syllabus, a convex mirror (R = 3 m, f = +1.5 m) has a bus at u = −5 m. What is the IMAGE distance v?Read the answer and worked solution →

Worked practice questions

As per your syllabus, what is the MIRROR FORMULA — relating object distance (u), image distance (v), and focal length (f)?

  1. 1/v + 1/u = 1/f
  2. 1/v × 1/u = 1/f
  3. v + u = f
  4. 1/v − 1/u = 1/f (this is the lens formula)
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Correct answer: A. 1/v + 1/u = 1/f

As per your syllabus, Eq 9.1, mirror formula = 1/v + 1/u = 1/f. The lens formula is 1/v − 1/u = 1/f (different sign).

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As per your syllabus, a NEGATIVE value of magnification m for a mirror indicates what?

  1. The image is virtual (erect)
  2. The image is at infinity
  3. The image is REAL (inverted)
  4. The image is point-sized
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Correct answer: C. The image is REAL (inverted)

As per your syllabus, §Magnification, negative m = real (inverted) image. Positive m = virtual (erect) image.

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As per your syllabus, if the radius of curvature of a spherical mirror is 20 cm, what is its focal length?

  1. 10 cm (since f = R/2)
  2. 20 cm
  3. 5 cm
  4. 40 cm
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Correct answer: A. 10 cm (since f = R/2)

As per your syllabus, f = R/2 = 20/2 = 10 cm.

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