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CUET UG Amines and Biomolecules — practice questions — page 2

Explore 168 free Amines and Biomolecules questions in CUET UG Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Amines and Biomolecules questions and exercises with answers

Showing questions 31–60 of 168.

Introducing halogen using copper powder and a halogen acid is the:Read the answer and worked solution →Iodobenzene is obtained by treating the diazonium salt with:Read the answer and worked solution →Coupling of benzenediazonium chloride with phenol gives:Read the answer and worked solution →Carbohydrates are defined as optically active polyhydroxy:Read the answer and worked solution →Carbohydrates are also known by which other name?Read the answer and worked solution →A carbohydrate that cannot be hydrolysed further is a:Read the answer and worked solution →Oligosaccharides give on hydrolysis how many monosaccharide units?Read the answer and worked solution →Polysaccharides are also called non-sugars because they are not:Read the answer and worked solution →Sugars that reduce Tollens' reagent are called:Read the answer and worked solution →A monosaccharide holding an aldehyde group is called an:Read the answer and worked solution →Glucose is an aldohexose also known as:Read the answer and worked solution →Prolonged heating of glucose with hydrogen iodide gives:Read the answer and worked solution →Glucose oxidised by bromine water yields:Read the answer and worked solution →Oxidation of glucose with nitric acid gives:Read the answer and worked solution →Glucose pentaacetate shows that glucose carries how many hydroxyls?Read the answer and worked solution →Commercial glucose is obtained by hydrolysing starch at:Read the answer and worked solution →The carbon whose hydroxyl decides alpha or beta glucose is called:Read the answer and worked solution →The six membered ring form of glucose is called the:Read the answer and worked solution →Fructose is best described as a:Read the answer and worked solution →The five membered ring form of fructose is called the:Read the answer and worked solution →Two monosaccharides joined through an oxygen atom share a:Read the answer and worked solution →Sucrose is a non reducing sugar because both its:Read the answer and worked solution →The laevorotatory mixture left after hydrolysing sucrose is called:Read the answer and worked solution →Maltose on hydrolysis gives two units of:Read the answer and worked solution →Lactose, the sugar of milk, is built from glucose and:Read the answer and worked solution →The water soluble component of starch is:Read the answer and worked solution →Amylopectin makes up roughly what share of starch?Read the answer and worked solution →Cellulose is a straight chain polymer built only from:Read the answer and worked solution →Carbohydrate is stored in the animal body as:Read the answer and worked solution →All proteins are polymers of which kind of amino acid?Read the answer and worked solution →

Worked practice questions

Introducing halogen using copper powder and a halogen acid is the:

  1. Galvanic reaction
  2. Gatterman reaction
  3. Grignard reaction
  4. Gattering reaction
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Correct answer: B. Gatterman reaction

1. Copper powder replaces the cuprous halide here. 2. The halogen acid supplies the halide ion. 3. This variant is the Gatterman reaction. _Source: syllabus Chemistry Part 2, Unit 9 'Amines'_

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Iodobenzene is obtained by treating the diazonium salt with:

  1. Potassium bromide
  2. Potassium bromate
  3. Potassium iodide
  4. Potassium iodate
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Correct answer: C. Potassium iodide

1. Iodine will not go into the ring by direct halogenation. 2. The diazonium route gets round that. 3. Potassium iodide supplies the iodide ion. _Source: syllabus Chemistry Part 2, Unit 9 'Amines'_

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Coupling of benzenediazonium chloride with phenol gives:

  1. o-hydroxyazobenzene
  2. p-hydroxynitrobenzene
  3. o-hydroxynitrobenzene
  4. p-hydroxyazobenzene
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Correct answer: D. p-hydroxyazobenzene

1. The diazonium ion attacks the phenol ring. 2. It goes to the position para to the hydroxyl group. 3. The coloured product is p-hydroxyazobenzene. _Source: syllabus Chemistry Part 2, Unit 9 'Amines'_

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