Start learning →

COMEDK Alcohols, Phenols and Ethers — practice questions

Explore 30 free Alcohols, Phenols and Ethers questions in COMEDK Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

Practise Alcohols, Phenols and Ethers with Quill →

Alcohols, Phenols and Ethers questions and exercises with answers

Showing questions 1–30 of 30.

How is glycerol (propane-1,2,3-triol) classified by the number of –OH groups it contains?Read the answer and worked solution →Arrange in increasing order of acidic strength: methanol, ethanol, water, phenol.Read the answer and worked solution →Ethanol is dehydrated with concentrated $\mathrm{H_2SO_4}$ at $443$ K (170 °C). What is the major product?Read the answer and worked solution →Hydrocarbons are organic compounds composed exclusively of:Read the answer and worked solution →In the presence of organic peroxides, addition of HBr to propene gives predominantly:Read the answer and worked solution →Wurtz reaction is used to prepare:Read the answer and worked solution →Match each scientist to their contributionRead the answer and worked solution →Ionic or covalent?Read the answer and worked solution →Complete the driver of bond formationRead the answer and worked solution →Single, double and triple bondsRead the answer and worked solution →True or false: Lewis structuresRead the answer and worked solution →Complete the definition of resonanceRead the answer and worked solution →Tap every bond parameter the chapter namesRead the answer and worked solution →True or false: ionic solidsRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Bonded pair or lone pair?Read the answer and worked solution →Flip and pair: term with meaningRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Order the reasoning: why resonance is neededRead the answer and worked solution →Reading the definitions backRead the answer and worked solution →True or false: what bond parameters affectRead the answer and worked solution →Bond parameters in useRead the answer and worked solution →Which parameter answers this?Read the answer and worked solution →True or false: resonanceRead the answer and worked solution →Order the steps: draw a Lewis structureRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Assertion and reason: structureRead the answer and worked solution →Flip and pair: parameter with what it measuresRead the answer and worked solution →

Worked practice questions

How is glycerol (propane-1,2,3-triol) classified by the number of –OH groups it contains?

  1. Monohydric alcohol
  2. Dihydric alcohol
  3. Trihydric alcohol
  4. Phenol
Show answer and solution

Correct answer: C. Trihydric alcohol

Glycerol has three hydroxyl groups (on C1, C2 and C3), making it a **trihydric** alcohol. Monohydric carries one –OH (e.g. ethanol) dihydric two (e.g. ethylene glycol).

Open this question →

Arrange in increasing order of acidic strength: methanol, ethanol, water, phenol.

  1. ethanol < methanol < water < phenol
  2. phenol < water < ethanol < methanol
  3. methanol < ethanol < water < phenol
  4. water < methanol < ethanol < phenol
Show answer and solution

Correct answer: A. ethanol < methanol < water < phenol

Approximate pKₐ values: phenol ≈ 10, water ≈ 15.7, methanol ≈ 15.5, ethanol ≈ 15.9. Lower pKₐ ⇒ stronger acid. Ordering ascending acidity: **ethanol < methanol < water < phenol**. **Why:** phenol's conjugate base (phenoxide) is stabilised by resonance into the aromatic ring, dramatically lowering its pKₐ versus aliphatic alcohols. Among the alcohols, the +I effect of larger alkyl groups *destabilises* the alkoxide (donates electron density) so ethanol is weaker than methanol.

Open this question →

Ethanol is dehydrated with concentrated $\mathrm{H_2SO_4}$ at $443$ K (170 °C). What is the major product?

  1. Diethyl ether
  2. Acetaldehyde
  3. Ethene
  4. Methanol
Show answer and solution

Correct answer: C. Ethene

**Temperature determines the product.** At ~170 °C with concentrated H₂SO₄, intramolecular dehydration (E1) of ethanol gives **ethene** plus water — the classic preparation of ethene from ethanol. At lower temperatures (≈ 140 °C, less acid) the reaction takes the *intermolecular* path: two ethanol molecules condense via loss of water to give **diethyl ether** instead. **Option B is therefore the answer for a *different* temperature regime — a common JEE trap.** Mechanism (E1, three steps): (i) protonation of the –OH, (ii) loss of H₂O to give a carbocation, (iii) loss of a β-proton to give the alkene.

Open this question →

How to practise

  1. Choose a Alcohols, Phenols and Ethers question and try to work out your answer.
  2. Open the question to check the correct answer and read its worked solution.
  3. Continue in the app for bite-sized lessons, explanations and review with Quill. You can start without creating an account.

More Chemistry topics